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How do you solve #6c-8-2c=-16#?

Answer 1

Hazel Anglin

#c = -2#

The like terms on the left side of the equation should first be grouped and combined:

#6c - 2c - 8 = -16#

#(6 - 2)c - 8 = -16#

#4c - 8 = -16#

Next, isolate the #c# terms on one side of the equation and the constants on the other side of the equation:

#4c - 8 color(red)( + 8) = -16 color(red)( + 8)#

#4c - 0 = -8#

#4c = -8#

Now we can solve for #c# while keeping the equation balanced:

#(4c)/(color(red)(4)) = -8/(color(red)(4)) #

#(color(red)(cancel(color(black)(4)))c)/color(red)(cancel(color(black)(4))) = -2#

#c = -2#

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Answer 2

Isaiah Anthony

To solve the equation 6c - 8 - 2c = -16, first, combine like terms:

6c - 2c - 8 = -16

4c - 8 = -16

Then, add 8 to both sides to isolate the variable:

4c - 8 + 8 = -16 + 8

4c = -8

Next, divide both sides by 4 to solve for c:

4c/4 = -8/4

c = -2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.