How do you solve #6(y-2)-3(y+1)=8 #?
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Nathan AxelTo solve the equation (6(y-2)-3(y+1)=8), you would first distribute the terms inside the parentheses, then combine like terms, and finally isolate the variable (y).
Here are the steps:
- Distribute: (6y - 12 - 3y - 3 = 8)
- Combine like terms: (6y - 3y - 12 - 3 = 8)
- Simplify: (3y - 15 = 8)
- Add 15 to both sides: (3y = 23)
- Divide both sides by 3: (y = \frac{23}{3})
So, the solution to the equation is (y = \frac{23}{3}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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