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How do you solve #6(x+4)-(x+3)=x-1#?

Answer 1

Avery Alexander

#color(green)(x = -11/2#

#6 ( x+4) - (x+3) = x-1#

#6 * ( x) + 6 * (4) - x - 3 = x-1#

#6x + 24 - x - 3 = x-1#

#6x - x - 3 + 24 = x-1#

#5x + 21 = x-1#

#5x -x = -1 - 21#

#4x = -22#

#x =- 22/4#

#x = -11/2#

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Answer 2

Abigail Allen

To solve the equation 6(x+4) - (x+3) = x - 1:

Distribute the 6: 6x + 24 - (x + 3) = x - 1
Distribute the negative sign inside the parentheses: 6x + 24 - x - 3 = x - 1
Combine like terms on the left side: 6x - x + 24 - 3 = x - 1
Simplify: 5x + 21 = x - 1
Subtract x from both sides to isolate terms with x: 5x + 21 - x = x - 1 - x
Simplify: 4x + 21 = -1
Subtract 21 from both sides: 4x + 21 - 21 = -1 - 21
Simplify: 4x = -22
Divide both sides by 4 to solve for x: 4x / 4 = -22 / 4
Simplify: x = -22/4 x = -11/2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.