How do you solve #6(x+3)+38=2#?

Answer 1

#color(green)(x = -9#

As we need to find the value of #x#, we try to transpose all the other terms to the right hand side.

When we translate 38 to the right, we obtain:

#6(x+3) = 2-38#
#6(x+3) = -36#

We can divide both sides by 6 to get rid of 6.

#(cancel(6)(x+3))/cancel6 = -36/6#
#x + 3 = -6#

When we translate 3 to the right, we obtain

#x = -6 - 3#
#color(green)(x = -9#
Test: Try substituting the value of #x# in the original equation and check if it's satisfied
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Answer 2

To solve the equation 6(x+3) + 38 = 2, follow these steps:

  1. First, distribute the 6 across the parentheses: 6x + 18.
  2. Combine like terms: 6x + 18 + 38 = 2.
  3. Simplify: 6x + 56 = 2.
  4. Subtract 56 from both sides: 6x = -54.
  5. Divide both sides by 6: x = -9.

So, the solution to the equation is x = -9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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