How do you solve #6=x/3+1#?
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Eli AssoulineTo solve the equation (6 = \frac{x}{3} + 1), first subtract 1 from both sides to isolate the term (\frac{x}{3}). This gives you (6 - 1 = \frac{x}{3}), which simplifies to (5 = \frac{x}{3}). Then, multiply both sides of the equation by 3 to get rid of the fraction, resulting in (5 \times 3 = x). Therefore, (x = 15).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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