How do you solve # 6(m - 2) + 14 = 3(m + 2) - 10 #?
See the entire solution process below:
First, multiply each term inside the parenthesis by the term outside the parenthesis to expand the terms in parenthesis on each side of the equation:
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To solve the equation 6(m - 2) + 14 = 3(m + 2) - 10, first distribute the terms inside the parentheses:
6m - 12 + 14 = 3m + 6 - 10
Combine like terms:
6m + 2 = 3m - 4
Subtract 3m from both sides:
6m - 3m + 2 = -4
Simplify:
3m + 2 = -4
Subtract 2 from both sides:
3m = -6
Divide both sides by 3:
m = -2
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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