How do you solve #6( m - 2) + 14= 3( m + 2) - 10#?

Answer 1

Genesis Allen

#m=2/3#

Expand the brackets on both sides:

#6m-12+14=3m+6-10#

Take away the #3m# from the right side of the equation:

#3m-12+14=+6-10#

Work out additions and subtractions:

#3m+2=+4#

Take away the #+2#:

#3m=2#

Divide both sides by #3#:

#(3m)/3=2/3#

So:

#m=2/3#

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Answer 2

Eli Assouline

m=2/3

So we just multiply the number before the bracket with all the numbers in the bracket. Simple algebra.

#6(m-2)+14=3(m+2)-10# #6m-12+14=3m+6-10# #3m -12 +14 =6 - 10# #3m =-6+10 +12 -14# #3m=22-20 = 3m=2# #(3m)/3 =2/3# #m = 2/3#

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Answer 3

Eva Abramson

To solve the equation (6(m - 2) + 14 = 3(m + 2) - 10), follow these steps:

Distribute the terms inside the parentheses: (6m - 12 + 14 = 3m + 6 - 10)
Combine like terms: (6m + 2 = 3m - 4)
Subtract (3m) from both sides: (6m - 3m + 2 = -4)
Simplify: (3m + 2 = -4)
Subtract 2 from both sides: (3m = -6)
Divide both sides by 3: (m = -2)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.