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How do you solve #6=\frac{1}{3}(3)+b#?

Answer 1

Savannah Anderson

#b=5#

#"note "1/3(3)=1/cancel(3)^1xxcancel(3)^1=1#

#rArr6=1+blarr" is the equation to be solved"#

#"subtract 1 from both sides"#

#6-1=cancel(1)cancel(-1)+b#

#rArrb=5" is the solution"#

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Answer 2

Nathan Axel

To solve the equation ( 6 = \frac{1}{3}(3) + b ), you can follow these steps:

Simplify the expression on the right-hand side of the equation:

[ \frac{1}{3}(3) = 1 ]

Substitute the simplified expression back into the equation:

[ 6 = 1 + b ]

Solve for ( b ) by isolating it on one side of the equation:

[ 6 - 1 = b ] [ b = 5 ]

Therefore, the solution to the equation is ( b = 5 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.