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How do you solve #-6( 4- x ) = 12x#?

Answer 1

Ethan Adkins

#x = -6#

#-6(4-x)=12x#

First, we want to simplify #-6(4-x)# using the distributive property:

Following this image, we know it becomes:
#color(blue)(-6(4-x) = (-6 * 4) + (-6 * -x) = -24 + 6x)#

Let's put that back into the equation:
#-24 + 6x = 12x#

Now subtract #color(blue)(6x)# from both sides of the equation:
#-24 + 6x quadcolor(blue)(-quad6x) = 12x quadcolor(blue)(-quad6x)#

#-24 = 6x#

Now divide both sides by #color(blue)6#:
#-24/color(blue)6 = (6x)/color(blue)6#

#-6 = x#

Therefore,
#x = -6#

Hope this helps!

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Answer 2

Hazel Anglin

To solve the equation ( -6(4 - x) = 12x ), you can follow these steps:

Distribute the -6 across the expression inside the parentheses: [ -6 \times 4 - (-6) \times x = 12x ]
Simplify both sides of the equation: [ -24 + 6x = 12x ]
Rearrange the equation by moving all terms involving ( x ) to one side: [ -24 = 12x - 6x ]
Combine like terms: [ -24 = 6x ]
Divide both sides by 6 to isolate ( x ): [ \frac{-24}{6} = x ]
Simplify: [ x = -4 ]

So, the solution to the equation is ( x = -4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.