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How do you solve # 6(-3v + 1) = 5(-2v - 2) #?

Answer 1

v = 2

The first step is to enlarge the brackets as follows: 6(-3v + 1) = (6 * -3v) + (6 * 1) = -18v + 6 5(-2v - 2) = (5 * -2v) + (5 * -2) = -10v - 10.

Consequently, -18 v + 6 = -10 v - 10

The equations can then be made simpler by adding the values to each side (keep in mind that you have to do the same operation on both sides when you add something to one): -18v + 6 (- 6) = -10v - 10 (- 6) -18v = -10v - 16

After that, we can use v to accomplish the same task: -18v (+ 10v) = -10v - 16 (+ 10v) -8v = -16

Next, calculate the value of v by dividing both sides by -8: v = 2.

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Answer 2

Abigail Allen

To solve the equation 6(-3v + 1) = 5(-2v - 2), follow these steps:

Distribute the constants: -18v + 6 = -10v - 10
Combine like terms: -18v + 10v = -10 - 6
Simplify: -8v = -16
Divide both sides by -8: v = 2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.