How do you solve # 6(3v + 1) = 5(2v  2) #?
v = 2
The first step is to enlarge the brackets as follows: 6(3v + 1) = (6 * 3v) + (6 * 1) = 18v + 6 5(2v  2) = (5 * 2v) + (5 * 2) = 10v  10.
Consequently, 18 v + 6 = 10 v  10
The equations can then be made simpler by adding the values to each side (keep in mind that you have to do the same operation on both sides when you add something to one): 18v + 6 ( 6) = 10v  10 ( 6) 18v = 10v  16
After that, we can use v to accomplish the same task: 18v (+ 10v) = 10v  16 (+ 10v) 8v = 16
Next, calculate the value of v by dividing both sides by 8: v = 2.
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To solve the equation 6(3v + 1) = 5(2v  2), follow these steps:

Distribute the constants: 18v + 6 = 10v  10

Combine like terms: 18v + 10v = 10  6

Simplify: 8v = 16

Divide both sides by 8: v = 2
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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