How do you solve #6( 2x + 5) <  78#?
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To solve the inequality (6(2x + 5) < 78), follow these steps:

Distribute the 6 on the left side: (12x + 30 < 78)

Move the constant term to the right side: (12x < 78  30) (12x < 108)

Divide both sides by 12 (since 12 is positive, inequality direction remains unchanged): (x < 108/12) (x < 9)
The solution to the inequality is (x < 9).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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