How do you solve #6+ 2x = 38#?

Answer 1

#x=16#

#6+2x=38# (Subtract 6 from both sides)
#2x=32# (Divide both sides by 2 to isolate the variable)
#x=16#

Enter the solution into the original equation to verify it:

#6+ 2(16) =38#
#6+32=38#
#38=38#
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Answer 2

#x=16#

So first you have to subtract #6# from both sides. When you subtract from #38#, you get #32#. Now you just have
#2x=32#
left. This is when you use division to get #x# by itself. Now you divide by #2# on both sides
#(2x)/2 = 32/2#
and you do that to get #x# alone. So now it's just
#x=16#
because #32/2# is #6#.
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Answer 3

To solve the equation 6 + 2x = 38, first subtract 6 from both sides to isolate the term with the variable:

2x = 38 - 6

Then simplify:

2x = 32

Now, divide both sides by 2 to solve for x:

x = 32 / 2

x = 16

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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