# How do you solve #|6- 2x | = 2| x - 3|#?

This equation is an identity, so true for any value of

So we find:

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To solve the equation (|6 - 2x| = 2|x - 3|), we need to consider two cases:

- When (6 - 2x \geq 0) and (x - 3 \geq 0).
- When (6 - 2x \geq 0) and (x - 3 < 0).

For case 1: [|6 - 2x| = 6 - 2x] [2|x - 3| = 2(x - 3)]

For case 2: [|6 - 2x| = -(6 - 2x)] [2|x - 3| = -2(x - 3)]

Solving each case separately will give us the solutions for (x).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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