How do you solve #6(2-x)+4x=-5(x+3)#?

Answer 1

Savannah Anderson

#x=-9#

#6 (2-x) + 4x = -5 (x+3)#

Six x (2) plus six x (-x) plus four times is five x (x) plus (-5) x (3).

#12 -6x+ 4x = -5x -15#

#12 -2x = -5x -15#

#12 +15 = -5x +2x#

#27 = -3x#

#x = 27/(-3)#

#x=-9#

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Answer 2

Genesis Allen

To solve the equation 6(2-x) + 4x = -5(x+3):

Distribute the terms: 12 - 6x + 4x = -5x - 15
Combine like terms: 12 - 2x = -5x - 15
Move variables to one side: 12 + 15 = -5x + 2x
Simplify: 27 = -3x
Divide by the coefficient of x: x = -9

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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