# How do you solve #6( 1- 7x ) \geq - 8x + 40#?

Distribute, then isolate variables. see below.

distribute the 6 to the parentheses.

subtract 40 from both sides

now we divide both sides by a form of one.

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To solve the inequality (6(1 - 7x) \geq -8x + 40):

- Expand and simplify both sides of the inequality.
- Combine like terms.
- Solve for (x).

(6(1 - 7x) \geq -8x + 40)

(6 - 42x \geq -8x + 40)

Add (42x) to both sides:

(6 \geq 34x + 40)

Subtract 40 from both sides:

(-34 \geq 34x)

Divide both sides by 34 (and reverse the inequality because dividing by a negative number):

(x \leq \frac{-34}{34})

(x \leq -1)

Therefore, the solution to the inequality is (x \leq -1).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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