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How do you solve -5y-5(-6-2y)=0?

Answer 1

Avery Alexander

#y=-6#

Distribute the bracket, collect terms in y on the left side of the equation and numeric values on the right side.

#rArr-5y+30+10y=0#

simplify left side by collecting like terms.

#rArr5y+30=0#

subtract 30 from both sides.

#5ycancel(+30)cancel(-30)=0-30#

#rArr5y=-30#

To solve for y, divide both sides by 5

#(cancel(5) y)/cancel(5)=(-30)/5#

#rArry=-6" is the solution"#

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Answer 2

Nathan Axel

To solve the equation -5y - 5(-6 - 2y) = 0, follow these steps:

Distribute the -5 to the terms inside the parentheses.
Combine like terms on both sides of the equation.
Isolate the variable term (in this case, y) on one side of the equation.
Solve for the variable by performing the necessary operations.

Here's a step-by-step breakdown:

-5y - 5(-6 - 2y) = 0

Distribute -5 to the terms inside the parentheses: -5y + 30 + 10y = 0

Combine like terms: (-5y + 10y) + 30 = 0 5y + 30 = 0

Isolate the variable term (5y): Subtract 30 from both sides: 5y + 30 - 30 = 0 - 30 5y = -30

Solve for y: Divide both sides by 5: 5y / 5 = -30 / 5 y = -6

Therefore, the solution to the equation is y = -6.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.