How do you solve #5y+3=3(y-3)-2(y+2)#?
Isaiah AnthonyBy signing up, you agree to our Terms of Service and Privacy Policy
Abigail AllenTo solve the equation (5y + 3 = 3(y - 3) - 2(y + 2)), first distribute the terms inside the parentheses:
[5y + 3 = 3y - 9 - 2y - 4]
Then, combine like terms:
[5y + 3 = y - 13]
Next, isolate the variable (y):
[5y - y = -13 - 3] [4y = -16]
Finally, solve for (y) by dividing both sides by 4:
[y = -4]
So, (y = -4).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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