How do you solve #5y - 16= 3y + 215#?

Answer 1

#y=231/2#

Step one:

Minus #3y# from both sides
#5y-3y-16=215#

Step two:

Add #16# to both sides
#5y-3y=215+16#

Step three:

Simplify

#2y=231#

Step four:

Divide both sides by #2#
#y=231/2 = 115.5#
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Answer 2

To solve the equation 5y - 16 = 3y + 215, you would first combine like terms on both sides of the equation. Then, you would isolate the variable term (in this case, y) by subtracting 3y from both sides. After that, you would isolate the constant term by adding 16 to both sides. Finally, you would divide both sides by the coefficient of y to solve for y. The steps would be as follows:

5y - 16 = 3y + 215

5y - 3y = 215 + 16

2y = 231

y = 231 / 2

y = 115.5

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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