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How do you solve #5x \leq 21+ 2x#?

Answer 1

Genesis Allen

#x <= 7#

#5x <= 21 + 2x#

Take away #2x# from every side.

#3x <= 21#

Divide each side by #3#.

#x<= 7#

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Answer 2

Kennedy Adams

To solve the inequality 5x ≤ 21 + 2x:

Subtract 2x from both sides to isolate the variable term on one side: 5x - 2x ≤ 21
Simplify the left side: 3x ≤ 21
Divide both sides by 3 to solve for x: x ≤ 7

Therefore, the solution to the inequality is x ≤ 7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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