How do you solve #5x + ( - 8) = 42#?

Answer 1

#x=10#

#5x + (-8) = 42# can be rewritten as
#5x - 8 = 42#
We want #x# by itself. Therefore, we add #8# on both sides.
#5x = 50#
Eliminate #5# to the right by dividing by #5# for both sides.
#x=10#.
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Answer 2

To solve (5x + (-8) = 42), follow these steps:

  1. Add 8 to both sides of the equation to isolate the term with the variable (x): [5x + (-8) + 8 = 42 + 8]

  2. Simplify both sides of the equation: [5x = 50]

  3. Divide both sides by 5 to solve for (x): [x = \frac{50}{5}]

  4. Simplify the expression: [x = 10]

So, the solution to the equation (5x + (-8) = 42) is (x = 10).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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