How do you solve # -5x+7 > -3#?

Answer 1

Solution of the inequality is #x<2#

Given:

The inequality # -5x+7 > -3#

Subtract #7# from both sides of the inequality

# rArr -5x+7-7 > -3-7#

# rArr -5x+cancel 7-cancel 7 > -3-7#

#rArr -5x > - 10#

Multiply both the sides by #(-1)#

Please remember to reverse the inequality

#rArr (-5x)(-1) < (- 10)(-1)#

#rArr 5x < 10#

Divide both sides by 5

#rArr (5x)/5 < 10/5#

#rArr (cancel 5x)/cancel 5 < cancel 10 ^ color(red)(2) /cancel 5#

#rArr x < 2#

Hence #x<2# is the required solution.

Verify this solution with the graph below:

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Answer 2

To solve the inequality -5x + 7 > -3, follow these steps:

  1. Subtract 7 from both sides: -5x > -3 - 7, which simplifies to -5x > -10.
  2. Divide both sides by -5. Remember, when dividing or multiplying an inequality by a negative number, flip the direction of the inequality sign: x < -10 / -5.
  3. Simplify: x < 2.

So, the solution to the inequality is x < 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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