How do you solve #5x+7=10# by clearing the fractions?

Answer 1

#x = 3/5#

#5x + 7 = 10#
Subtract both sides by #color(red)7#
#5x + 7 - color(red)7 = 10 - color(red)7#
#5x + 0 = 10 - 7#
#5x = 3#
Divide both sides by #color(red)5#
#(5x)/color(red)5 = 3/color(red)5#
#cancel((5) x)/cancel5 = 3/5#
#x = 3/5#
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Answer 2

To solve the equation 5x + 7 = 10 by clearing the fractions, follow these steps:

  1. Subtract 7 from both sides to isolate the term with the variable: 5x = 10 - 7

  2. Simplify the right side of the equation: 5x = 3

  3. Divide both sides by 5 to solve for x: x = 3/5

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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