How do you solve #|5x-5|=15#?
To solve this you should look at the two equations formed by this to find the answer(s). It is similar to the way you would look at quadratic equations.
When you take off the absolute value you have two separate equations.
You have to peruse both equations to find the solution(s). Both answers may not always work. Remember to plug the answer back in to check.
1st Equation:
2nd Equation:
If you plug these answers back into the original equation, you would find that they both work.
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To solve the equation |5x - 5| = 15, you would split it into two cases based on the absolute value:
- 5x - 5 = 15
- -(5x - 5) = 15
Then solve each case separately:
-
5x - 5 = 15 Add 5 to both sides: 5x = 20 Divide by 5: x = 4
-
-(5x - 5) = 15 Distribute the negative sign: -5x + 5 = 15 Subtract 5 from both sides: -5x = 10 Divide by -5: x = -2
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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