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How do you solve #5x + 4< 3( 5x - 2)#?

Answer 1

Abigail Allen

#x>1#

#"distribute the bracket on the right side"#

#5x+4<15x-6#

#"collect terms in x on one side and numeric values on"# #"the other side"#

#"subtract "5x" from both sides"#

#cancel(5x)cancel(-5x)+4<15x-5x-6#

#4<10x-6#

#"add 6 to both sides"#

#4+6<10x#

#10<10x#

#"divide both sides by 10"#

#1< x" or "x>1#

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Answer 2

Isaiah Anthony

To solve ( 5x + 4 < 3(5x - 2) ), follow these steps:

Distribute ( 3 ) into ( 5x - 2 ) to get ( 15x - 6 ).
Simplify the inequality to ( 5x + 4 < 15x - 6 ).
Subtract ( 5x ) from both sides to get ( 4 < 10x - 6 ).
Add ( 6 ) to both sides to get ( 10 < 10x ).
Divide both sides by ( 10 ) to isolate ( x ), yielding ( \frac{10}{10} < x ).
Simplify to ( 1 < x ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #5x + 4&lt; 3( 5x - 2)#?

How do you solve #5x + 4< 3( 5x - 2)#?