How do you solve #-5x = -3x^2# using the quadratic formula?
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Solution 1)
Solution 2)
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To solve the equation -5x = -3x^2 using the quadratic formula, first, rewrite the equation in standard form: 3x^2 - 5x = 0. Then, apply the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a), where a = 3, b = -5, and c = 0. Substituting these values into the quadratic formula yields: x = (5 ± √((-5)^2 - 4(3)(0))) / (2(3)). Simplify the expression inside the square root: x = (5 ± √(25)) / 6. Since √(25) = 5, the expression simplifies further to: x = (5 ± 5) / 6. This results in two possible solutions: x = (5 + 5) / 6 and x = (5 - 5) / 6. Therefore, the solutions are x = 10/6 or x = 0/6, which simplify to x = 5/3 and x = 0.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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