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How do you solve #5x^2 = –45x#?

Answer 1

Answer is
#x=-9#or #x=0#

#The# #above# #equation# #5x^2 = -45x# Do not divide both sides by #x#. You will lose an answer. Instead, get both terms on one side and factor: #5x^2+45x = 0#

now we got, #5x(x+9) = 0#

So,

Either #5x=0# or #x+9=0#

Either #x=0# or #x=-9#.

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Answer 2

Nathan Axel

To solve the equation 5x^2 = -45x, first, move all terms to one side to set the equation to zero: 5x^2 + 45x = 0. Next, factor out the common term, which is x: x(5x + 45) = 0. Then, apply the zero-product property, setting each factor equal to zero: x = 0 and 5x + 45 = 0. Solve the second equation for x: 5x = -45, x = -45/5, x = -9. Therefore, the solutions to the equation are x = 0 and x = -9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.