How do you solve #|5x+2|>=|3x-4|#?
Solution :
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To solve the inequality |5x + 2| ≥ |3x - 4|, you need to consider two cases:
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When 5x + 2 ≥ 0 and 3x - 4 ≥ 0:
- Solve 5x + 2 ≥ 3x - 4: 5x + 2 ≥ 3x - 4 2x ≥ -6 x ≥ -3
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When 5x + 2 < 0 and 3x - 4 < 0:
- Solve 5x + 2 ≤ -(3x - 4): 5x + 2 ≤ -3x + 4 8x ≤ 2 x ≤ 1/4
Therefore, the solution set for the inequality |5x + 2| ≥ |3x - 4| is x ≤ 1/4 or x ≥ -3.
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To solve the inequality (|5x+2| \geq |3x-4|), we consider different cases based on the possible signs of (5x+2) and (3x-4).
Case 1: (5x+2) and (3x-4) are both non-negative or both non-positive: In this case, the absolute value inequality simplifies to (5x+2 \geq 3x-4). Solve for (x) to find the solution.
Case 2: (5x+2) is non-negative and (3x-4) is non-positive: In this case, the absolute value inequality simplifies to (5x+2 \geq -(3x-4)). Solve for (x) to find the solution.
Case 3: (5x+2) is non-positive and (3x-4) is non-negative: In this case, the absolute value inequality simplifies to (-(5x+2) \geq 3x-4). Solve for (x) to find the solution.
Case 4: (5x+2) and (3x-4) are both non-zero with opposite signs: In this case, the absolute value inequality simplifies to (-(5x+2) \geq -(3x-4)). Solve for (x) to find the solution.
Once you have solved each case, you should consider the intersection of all solutions to obtain the final solution set for the inequality.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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