How do you solve #5x^2  2x +4 = 0# by quadratic formula?
Solve by quadratic formula:
quadratic formula:
Simplify.
Prime factorize the number of the square root.
Simplify.
Reduce.
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To solve the quadratic equation (5x^2  2x + 4 = 0) using the quadratic formula, follow these steps:

Identify the coefficients (a), (b), and (c) in the quadratic equation (ax^2 + bx + c = 0).

Apply the quadratic formula: (x = \frac{{b \pm \sqrt{{b^2  4ac}}}}{{2a}}).

Substitute the values of (a), (b), and (c) into the quadratic formula.

Calculate the discriminant ((b^2  4ac)) to determine the nature of the roots:
 If the discriminant is positive, there are two real roots.
 If the discriminant is zero, there is one real root (a repeated root).
 If the discriminant is negative, there are two complex roots.

Substitute the values of (a), (b), and (c) into the quadratic formula and calculate the roots by performing the arithmetic operations.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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