How do you solve #5x^2 = 100# by factoring?

Answer 1

Make the LHS quadratic and RHS = 0

#5x^2 = 100# #x^2=20 # #x^2-20=0 # #(x+sqrt(20))(x-sqrt(20))=0# #(x+2sqrt(5))(x-2sqrt(5))=0# #x=-2sqrt(5)# or #x=2sqrt(5)#
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Answer 2

To solve 5x^2 = 100 by factoring, follow these steps:

  1. Start by dividing both sides of the equation by 5 to isolate x^2: x^2 = 20

  2. Rewrite the equation in the form of a quadratic equation: x^2 - 20 = 0

  3. Factor the quadratic equation: (x + √20)(x - √20) = 0

  4. Apply the square root property to solve for x: x + √20 = 0 or x - √20 = 0

  5. Solve for x in each equation: x = -√20 or x = √20

  6. Simplify the square roots: x = -2√5 or x = 2√5

So, the solutions to the equation 5x^2 = 100 by factoring are x = -2√5 and x = 2√5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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