How do you solve #5x - 16\frac { 3} { 4} = - 5\frac { 1} { 4}#?

Answer 1

Combine the two fractions and then divide to solve for #x#
resulting in #x = 2 3/10 #

Collect the fraction terms on one side.

# 5x - 16 3/4 + 16 3/4 = - 5 1/4 + 16 3/4#

Adding the two fractions gives

# 5x = 11 2/4# This reduces to
# 5x = 11 1/2# Now divide by 5
# (5x)/ 5 = 11/5 +(1/2)/5# This gives
# x = 2 1/5 + 1/10#
# x= 2 2/10 + 1/10" "# common denominators
# x = 2 3/10" " # so the final answer is
#x = 2 3/10 #
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Answer 2

#x= 2 3/10#

#5x-16 3/4 = -5 1/4" "larr " add " 16 3/4# to both sides:
#5x = +16 3/4 -5 1/4 " "larr# add the fractions:
#5x = 11 1/2" "larr# change to an improper fraction
#5x = 23/2" "larr# cross multiply
#10x= 23#
#x = 23/10#
#x = 2 3/10" "larr# answer as a mixed fraction
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Answer 3

To solve the equation 5x - 16⅜ = -5¼, you first need to isolate the variable x. Here are the steps:

  1. Add 16⅜ to both sides of the equation: 5x - 16⅜ + 16⅜ = -5¼ + 16⅜ 5x = 11

  2. Divide both sides of the equation by 5: 5x/5 = 11/5 x = 11/5

So, the solution to the equation is x = 11/5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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