How do you solve #5x+1/3=2x-3/2#?

Answer 1

#x = -11/18#

You must first transpose the terms with the given variable on one side of the equation and leave the terms without the variable on the other side in order to isolate the variable and solve this equation.

#5x + 1/3 = 2x - 3/2# #5x - 2x = -3/2 - 1/3#

To obtain the final answer, transpose the equation and then simplify it.

#5x - 2x = -3/2 -1/3# #3x = -9/6 - 2/6# #3x = -11/6# #x = -11/18#
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Answer 2

To solve the equation (5x + \frac{1}{3} = 2x - \frac{3}{2}), follow these steps:

  1. Get rid of the fractions by multiplying every term by the least common multiple of the denominators, which is 6.
  2. After multiplying, the equation becomes (30x + 2 = 12x - 9).
  3. Rearrange the equation by bringing like terms together. Subtract (12x) from both sides and add 9 to both sides.
  4. After rearranging, the equation becomes (18x = -11).
  5. Finally, solve for (x) by dividing both sides by 18.

The solution is (x = -\frac{11}{18}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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