How do you solve #-5n-8(1+7n)=-8#?

Answer 1

#n=0#

#-5n-8(1-7n)=-8# Open the brackets #-5n-8+56n=-8# Add both side 8 #-5n-8+56n+8=-8+8# #51n=0# #n=0#
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Answer 2

#n=0#

#"distribute bracket and collect like terms"#
#-5n-8-56n=-8#
#rArr-61n-8=-8#
#"add 8 to both sides"#
#-61ncancel(-8)cancel(+8)=-8+8#
#rArr-61n=0#
#rArrn=0#
#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=0-8(1+0)=0-8=-8=" right"#
#rArrn=0" is the solution"#
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Answer 3

#n=0#

#-5n-8(1+7n)=-8#
Expanding: #-5n-8(1)-8(7n)=-8# #=-5n-8-56n=-8#
Adding 8 to both sides: #=-5ncancel(-8)cancel(+8)-56n=cancel(-8)cancel(+8)# #=61n=0#
Dividing both sides by 61: #(cancel61n)/cancel61=0/61=0#
#rArrn=0#
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Answer 4

To solve the equation -5n - 8(1 + 7n) = -8, first distribute the -8: -5n - 8 - 56n = -8 Combine like terms: -5n - 56n - 8 = -8 Combine like terms again: -61n - 8 = -8 Add 8 to both sides: -61n = 0 Divide both sides by -61: n = 0

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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