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How do you solve #(5/(y+5)) = (4/(y-3)) #?

Answer 1

Savannah Anderson

#color(green)(y=35#

#(5/(y+5))=(4/(y-3))#

Remove the brackets:

#rarr5/(y+5)=4/(y-3)#

Cross multiply #color(blue)(a/b=c/d,ad=bc#

#rarr5(y-3)=4(y+5)#

Use distributive property #color(orange)(a(b+c)=ab+ac#

#rarr5y-15=4y+20#

Subtract #4y# both sides:

#rarry-15=20#

Add #15# both sides:

#rArrcolor(green)(y=35#

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Answer 2

Jameson Allen

To solve the equation (5/(y+5)) = (4/(y-3)), you can start by cross-multiplying. Multiply 5 by (y-3) and 4 by (y+5). This gives you 5(y-3) = 4(y+5). Expand the equation by distributing the numbers, which results in 5y - 15 = 4y + 20. Next, isolate the variables by moving all the y terms to one side and the constant terms to the other side. Subtract 4y from both sides, which gives you y - 15 = 20. Then, add 15 to both sides to get y = 35. Therefore, the solution to the equation is y = 35.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.