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How do you solve #5/( y - 2) = y+2#?

Answer 1

Eli Assouline

#5/(y-2)=y+2# or #(y-2)(y+2)=5# or #y^2-4=5# or #y^2=5+4# or #y^2=9# or #y=sqrt9# or #y=+-3#

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Answer 2

Ethan Adkins

To solve the equation 5/(y - 2) = y + 2, you can start by multiplying both sides of the equation by (y - 2) to eliminate the denominator. This gives you 5 = (y + 2)(y - 2). Expanding the right side of the equation, you get 5 = y^2 - 4. Rearranging the equation, you have y^2 - 4 - 5 = 0, which simplifies to y^2 - 9 = 0. Factoring the quadratic equation, you have (y - 3)(y + 3) = 0. Setting each factor equal to zero, you find y = 3 or y = -3. Therefore, the solutions to the equation are y = 3 and y = -3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.