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How do you solve # 5 / (y - 2) = y + 2#?

Answer 1

Genesis Allen

#y_1=3 or y_2=-3#

#5/(y-2)=y+2|*(y-2)# #5=(y+2)(y-2)# #5=y^2-2^2|+2^2# #9=y^2|sqrt()# #+-3=y# #y_1=3 or y_2=-3#

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Answer 2

Kennedy Adams

To solve the equation 5 / (y - 2) = y + 2, you can start by multiplying both sides of the equation by (y - 2) to eliminate the denominator. This gives you 5 = (y + 2)(y - 2). Expanding the right side of the equation, you get 5 = y^2 - 4. Rearranging the equation, you have y^2 - 4 - 5 = 0. Simplifying further, you get y^2 - 9 = 0. Factoring the equation, you have (y - 3)(y + 3) = 0. Setting each factor equal to zero, you find y - 3 = 0 or y + 3 = 0. Solving these equations, you get y = 3 or y = -3. Therefore, the solutions to the equation 5 / (y - 2) = y + 2 are y = 3 and y = -3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.