How do you solve #5(x+4)=4x+15#?

Answer 1

#x = -5#

First, use the distributive property shown below to simplify #5(x+4)#:

Following this image, we know that:
#5(x+4) = (5 * x) + (5 * 4) = 5x + 20#

Put that back into the equation:
#5x + 20 = 4x + 15#

Now subtract #color(blue)(4x)# from both sides of the equation:
#5x + 20 quadcolor(blue)(-quad4x) = 15 quadcolor(blue)(-quad15)#

#x + 20 = 15#

Now subtract #color(blue)20# from both sides of the equation:
#x + 20 quadcolor(blue)(-quad20) = 15 quadcolor(blue)(-quad20)#

#x = -5#

Hope this helps!

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Answer 2

To solve the equation 5(x+4) = 4x + 15, first distribute 5 to both terms inside the parentheses:

5x + 20 = 4x + 15

Next, move all terms involving x to one side of the equation:

5x - 4x = 15 - 20 x = -5

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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