How do you solve # 5 |x - 3| >=20#?
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To solve ( 5 |x - 3| \geq 20 ):
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Divide both sides by 5: ( |x - 3| \geq 4 ).
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Solve for two cases:
- ( x - 3 \geq 4 ) and ( x - 3 \leq -4 ).
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Solve each case separately:
- Case 1: ( x - 3 \geq 4 )
- Add 3 to both sides: ( x \geq 7 ).
- Case 2: ( x - 3 \leq -4 )
- Add 3 to both sides: ( x \leq -1 ).
- Case 1: ( x - 3 \geq 4 )
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Combine the solutions:
- The solution is ( x \geq 7 ) or ( x \leq -1 ).
Therefore, the solution to ( 5 |x - 3| \geq 20 ) is ( x \geq 7 ) or ( x \leq -1 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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