How do you solve #5 - x = 16#?

Answer 1

See a solution process below:

One way to solve this problem is to add #color(red)(x)# and subtract #color(blue)(16)# from each side of the equation to solve for #x# while keeping the equation balanced:
#5 - color(blue)(16) - x + color(red)(x) = 16 - color(blue)(16) + color(red)(x)#
#-11 - 0 = 0 + x#
#-11 = x#
#x = -11#
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Answer 2

You have to rearrange the equation.

Move #x# to the other side so you get
#5=16+x#
Then you move #16# to the other side so you get
#5-16=x#

You simply then simplify it to obtain

#-11 = x#
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Answer 3

[ x = -11 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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