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How do you solve #5+ 8x = 37#?

Answer 1

Hazel Anglin

The answer is #x = 4#.

First, you have to isolate the variable.

So subtract #5# on both sides.

#5 + 8x = 37# #-># #8x = 32#

And then divide by #8# on both sides

#8x = 32# #-># #x = 4#

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Answer 2

Kennedy Adams

#x = 4#

Let's see the problem again:

#5 + 8x = 37#

First, you subtract 5 from 5, after, you subtract 5 from 37. Now our problem should look like this:

#8x = 32#

Now, you divide #8x# and #32# both by 8. 8x divided by 8, the two 8's eliminate each other, so for the 8, you are left with just:

#x#

Now, lastly, you divide 32 by 8, which is 4. You are left with:

#color(red)(x = 4#

Hope this helps! :)

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Answer 3

Avery Alexander

To solve the equation (5 + 8x = 37), follow these steps:

Subtract 5 from both sides of the equation: [5 + 8x - 5 = 37 - 5]
Simplify both sides: [8x = 32]
Divide both sides by 8: [8x \div 8 = 32 \div 8]
Simplify: [x = 4]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.