How do you solve #5+ 8x = 37#?
The answer is
First, you have to isolate the variable.
Here's a link you can use if you still have trouble with the concept: https://tutor.hix.ai
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Let's see the problem again:
First, you subtract 5 from 5, after, you subtract 5 from 37. Now our problem should look like this:
Now, lastly, you divide 32 by 8, which is 4. You are left with:
Hope this helps! :)
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To solve the equation (5 + 8x = 37), follow these steps:

Subtract 5 from both sides of the equation: [5 + 8x  5 = 37  5]

Simplify both sides: [8x = 32]

Divide both sides by 8: [8x \div 8 = 32 \div 8]

Simplify: [x = 4]
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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