How do you solve 5ー8x=11?

Answer 1

#x = -3/4#

Here's how I did it:

#5-8x = 11#

In equations, we know that one side equals the other, so anything we do on one side of the equation must also be done on the other side.

Keeping this in mind, we can subtract #5# from both sides of the equation:
#5quadcolor(red)(-quad5) - 8x = 11quadcolor(red)(-quad5)#
#-8x = 6#
Now we divide both sides by #-8#: #x = -6/8#
We can still simplify this to: #x = -3/4# because #(-6/8 -:2/2 = -3/4)#

Hope this helps!

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Answer 2

To solve the equation 5 - 8x = 11, you first isolate the variable term by subtracting 5 from both sides of the equation. This yields -8x = 6. Then, divide both sides by -8 to solve for x. Thus, x = -6/8, which simplifies to x = -3/4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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