How do you solve #5/6x-2x+4/3=5/3#?

Answer 1

Look, in a way, 2 doesn't mean only 2, it also means #2/1,4/2,6/3,8/4.....# till infinity Looking in that way, And also transferring #4/3# #(5x-12x)/6=5/3-4/3# Solve #(-7x)/6=1/3# Transfer 6 to RHS to multiply #1/3# by 6 #-7x=1/cancel3^1xxcancel6^2# #-7x=2# Transfer -7 to RHS, to divide 2 by -7 #x=2/-7#

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Answer 2

Nathan Axel

To solve the equation 5/6x - 2x + 4/3 = 5/3:

Combine like terms: 5/6x - 2x can be combined to (5/6 - 2)x.
Simplify the expression: (5/6 - 2) = (5/6 - 12/6) = -7/6.
Rewrite the equation: (-7/6)x + 4/3 = 5/3.
Subtract 4/3 from both sides: (-7/6)x = 5/3 - 4/3 = 1/3.
Multiply both sides by -6/7 to isolate x: x = (1/3) * (-6/7) = -2/7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.