How do you solve #5(-6-3d)=3(8+7d)#?

Answer 1

#d=-1.5#

We use distribution to find a solution.

#5(-6-3d)=3(8+7d)#
This means that we "distribute" the #5# to everything in the parenthesis and "distribute" the #3# to everything to its parenthesis:
#-30-15d=24+21d#
Now we need to put all the variables on one side and the numbers on the other side of the equation: #-36d=54#
#d=-1.5#

I hope this is useful.

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Answer 2

#d=-3/2#

#5(-6-3d)=3(8+7d)# #rArr -30-15d=24+21d# #rArr 36d=-54# #rArr d=-54/36# #:. d=-3/2#

That is all. I hope this helps.

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Answer 3

To solve the equation 5(-6-3d)=3(8+7d):

  1. Distribute the numbers inside the parentheses.
  2. Combine like terms on each side of the equation.
  3. Move all the terms involving the variable (in this case, d) to one side of the equation.
  4. Solve for the variable (d).

Here are the steps:

  1. (5(-6) + 5(-3d) = 3(8) + 3(7d))
  2. (-30 - 15d = 24 + 21d)
  3. Add 15d to both sides: (-30 = 24 + 36d)
  4. Subtract 24 from both sides: (-54 = 36d)
  5. Divide both sides by 36: (d = -\frac{3}{2})

So, the solution to the equation is (d = -\frac{3}{2}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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