How do you solve #5/6(12p+4)=-13p+4#?

Answer 1

See the entire solution process below:

First, multiply both sides of the equation by #color(red)(6)# to eliminate the fraction and keep the equation balanced:
#color(red)(6) xx 5/6(12p + 4) = color(red)(6)(-13p + 4)#
#cancel(color(red)(6)) xx 5/color(red)(cancel(color(black)(6)))(12p + 4) = color(red)(6)(-13p + 4)#
#5(12p + 4) = color(red)(6)(-13p + 4)#
#60p + 20 = -78p + 24#
Next add #color(red)(78p)# and subtract #color(blue)(20)# from each side of the equation to isolate the #p# terms while keeping the equation balanced:
#60p + 20 + color(red)(78p) - color(blue)(20) = -78p + 24 + color(red)(78p) - color(blue)(20)#
#60p + color(red)(78p) + 20 - color(blue)(20) = -78p + color(red)(78p) + 24 - color(blue)(20)#
#138p + 0 = 0 + 4#
#138p = 4#
Now, divide each side of the equation by #color(red)(138)# to solve for #p# while keeping the equation balanced:
#(138p)/color(red)(138) = 4/color(red)(138)#
#(color(red)(cancel(color(black)(138)))p)/cancel(color(red)(138)) = 2/69#
#p = 2/69#
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Answer 2

To solve the equation ( \frac{5}{6}(12p+4)=-13p+4 ):

  1. Distribute ( \frac{5}{6} ) to ( 12p ) and ( 4 ) to get ( \frac{5}{6} \times 12p + \frac{5}{6} \times 4 = -13p + 4 ).
  2. Simplify both sides of the equation.
  3. Combine like terms.
  4. Solve for ( p ).
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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