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How do you solve #5=5(y-2)# using the distributive property?

Answer 1

Nathan Axel

#color(green)(y=3)#
#color(white)("XXX")#see below for use of the distributive property in this solution

According to the distributive property #color(white)("XXX")5(y-2)=5 * y - 5 * 2= 5y-10#

So #color(white)("XXX")5=5(y-2)# is equivalent to #color(white)("XXX")5=5y-10#

Adding #10# to both sides: #color(white)("XXX")15=5y#

Then dividing by #5#: #color(white)("XXX")3=ycolor(white)("XXX")#or more commonly: #y=3#

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Answer 2

Avery Alexander

To solve the equation 5 = 5(y - 2) using the distributive property, distribute 5 across the parentheses, yielding 5y - 10. Then, isolate the variable y by adding 10 to both sides of the equation, resulting in 5y = 15. Finally, divide both sides by 5 to find the value of y, which is 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.