How do you solve #5- 4x + 8+ 2x + 3x - 4= 3+ 3\cdot 4#?

Question

Eva Abramson · Accepted Answer

See the entire solution process below:

First, on the left side of the equation, group and combine like terms: #-4x + 2x + 3x + 5 + 8 - 4 = 3 + 3 * 4# #(-4 + 2 + 3)x + (5 + 8 - 4) = 3 + 3 * 4# #1x + 9 = 3 + 3 * 4# #x + 9 = 3 + 3 * 4# The right side of the equation is then made simpler by adhering to the standard operator order rules, which call for multiplying before adding: #x + 9 = 3 + color(red)(3 * 4)# #x + 9 = 3 + 12# #x + 9 = 15# Now, subtract #color(red)(9)# from each side of the equation to solve for #x# while keeping the equation balanced: #x + 9 - color(red)(9) = 15 - color(red)(9)# #x + 0 = 6# #x = 6#

Ethan Adkins · Answer

undefined To solve the equation 5 - 4x + 8 + 2x + 3x - 4 = 3 + 3 * 4:

1. Combine like terms on both sides of the equation.
2. Simplify each side of the equation.
3. Isolate the variable term on one side of the equation.
4. Solve for the variable.

The steps are as follows:

5 - 4x + 8 + 2x + 3x - 4 = 3 + 3 * 4
Combine like terms:
(5 + 8 - 4) + (-4x + 2x + 3x) = 3 + 12
9 - 4x + 5x = 15
Combine like terms again:
9 + x = 15
Isolate the variable term:
x = 15 - 9
x = 6

Therefore, the solution to the equation is x = 6.