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How do you solve #-5<=4r+3#?

Answer 1

Eva Abramson

#r>= -2#

# "isolate" 4r "by subtracting 3 from both sides" #

Number-5-3<=4rcancel(+3)cancel(-3)#

#rArr-8<=4r#

# "divide both sides by 4" #

#4<=cancel(4)/cancel(4) r# #(-8)/4

"r>= -2#" or "#rArr-2<=r"

"in interval notation" #r in[-2,oo)larrcolor(blue)#

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Answer 2

Genesis Allen

To solve the inequality -5 ≤ 4r + 3, first subtract 3 from both sides to isolate the term with r:

-5 - 3 ≤ 4r

Simplify:

-8 ≤ 4r

Next, divide both sides by 4:

-8/4 ≤ r

Simplify:

-2 ≤ r

So, the solution is r ≥ -2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #-5&lt;=4r+3#?

How do you solve #-5<=4r+3#?