How do you solve #5/(3x)+7/3=5#?
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To solve the equation 5/(3x) + 7/3 = 5, you can follow these steps:

Start by subtracting 7/3 from both sides of the equation to isolate the term with the variable: 5/(3x) = 5  7/3.

Simplify the right side of the equation: 5  7/3 = 15/3  7/3 = 22/3.

Now, multiply both sides of the equation by 3 to eliminate the fraction: 3 * (5/(3x)) = 3 * (22/3).

Simplify both sides: 5/x = 22.

To isolate the variable, multiply both sides of the equation by x: x * (5/x) = x * (22).

Simplify: 5 = 22x.

Divide both sides of the equation by 22 to solve for x: 5 / 22 = x.

The final solution is x = 5/22.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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