How do you solve #5/(3x)+7/3=-5#?
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To solve the equation 5/(3x) + 7/3 = -5, you can follow these steps:
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Start by subtracting 7/3 from both sides of the equation to isolate the term with the variable: 5/(3x) = -5 - 7/3.
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Simplify the right side of the equation: -5 - 7/3 = -15/3 - 7/3 = -22/3.
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Now, multiply both sides of the equation by 3 to eliminate the fraction: 3 * (5/(3x)) = 3 * (-22/3).
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Simplify both sides: 5/x = -22.
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To isolate the variable, multiply both sides of the equation by x: x * (5/x) = x * (-22).
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Simplify: 5 = -22x.
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Divide both sides of the equation by -22 to solve for x: 5 / -22 = x.
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The final solution is x = -5/22.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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