How do you solve #5/(3x)+7/3=-5#?

Answer 1

#x=-5/22#

#5/(3x)+7/3=-5# or #5/(3x)=-7/3-5# or #5/(3x)=(-7-15)/3# or #5/(3x)=-22/3# or #3x/5=-3/22# or #x/5=-1/22# or #x=-5/22#
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Answer 2

To solve the equation 5/(3x) + 7/3 = -5, you can follow these steps:

  1. Start by subtracting 7/3 from both sides of the equation to isolate the term with the variable: 5/(3x) = -5 - 7/3.

  2. Simplify the right side of the equation: -5 - 7/3 = -15/3 - 7/3 = -22/3.

  3. Now, multiply both sides of the equation by 3 to eliminate the fraction: 3 * (5/(3x)) = 3 * (-22/3).

  4. Simplify both sides: 5/x = -22.

  5. To isolate the variable, multiply both sides of the equation by x: x * (5/x) = x * (-22).

  6. Simplify: 5 = -22x.

  7. Divide both sides of the equation by -22 to solve for x: 5 / -22 = x.

  8. The final solution is x = -5/22.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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