How do you solve #5/3x-4/3x-1=8#?

Answer 1

#x=27#

Given: #5/3x-4/3x-1=8#

Combine terms that are similar.

#=>1/3x-1=8#
Add #1# to both sides.
#=>1/3x-color(red)cancelcolor(black)1+color(red)cancelcolor(black)1=8+1#
#=>1/3x=9#
Multiply by #3# on both sides to find #x#.
#=>1/(color(red)cancelcolor(black)3)x*color(red)cancelcolor(black)3=9*3#
#=>x=27#
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Answer 2

To solve the equation 5/3x - 4/3x - 1 = 8, first, combine like terms to simplify the left side of the equation. Then, isolate the variable x by performing the necessary operations.

Step 1: Combine like terms: 5/3x - 4/3x = (5/3 - 4/3)x = (1/3)x

Step 2: Rewrite the equation with the simplified expression: (1/3)x - 1 = 8

Step 3: Add 1 to both sides of the equation to isolate the term with x: (1/3)x = 8 + 1 = 9

Step 4: Multiply both sides of the equation by 3 to eliminate the fraction: 3 * (1/3)x = 3 * 9 x = 27

Therefore, the solution to the equation 5/3x - 4/3x - 1 = 8 is x = 27.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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