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How do you solve #5(2x - 7) = 33 - 3(6x + 4)#?

Answer 1

Abigail Allen

# x = 2 #

# 5 ( 2x - 7) = 33 - 3 ( 6x + 4)#

# 5 * ( 2x) + 5 * ( - 7) = 33 + (- 3) * ( 6x ) + ( -3) * (4)#

# 10x - 35 = 33 -18x -12 #

# 10x + 18x = 33 + 35 -12 #

# 28x = 56 #

Number x equals 56 / 28.

# x = 2 #

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Answer 2

Nathan Axel

To solve the equation 5(2x - 7) = 33 - 3(6x + 4):

Distribute the terms inside the parentheses on both sides.
Combine like terms on each side of the equation.
Move all terms involving x to one side of the equation and constants to the other side.
Combine like terms again.
Divide both sides by the coefficient of x to solve for x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.