How do you solve #5(2x+6)=-4(-5-2x)+3x#?

Question

Isaiah Anthony · Accepted Answer

#x = 10#

#5(2x+6) = -4(-5-2x) + 3x#

Use the distributive property to simplify/expand: #10x + 30 = 20 + 8x + 3x#

Simplify the right side: #10x + 30 = 20 + 11x#

Subtract #color(blue)(11x)# from both sides: #10x + 30 quadcolor(blue)(-quad11x) = 20 + 11x quadcolor(blue)(-quad11x)#

#-x + 30 = 20#

Subtract #color(blue)30# from both sides: #-x + 30 quadcolor(blue)(-quad30) = 20 quadcolor(blue)(-quad30)#

#-x = -10#

Divide both sides by #color(blue)(-1)#: #(-x)/color(blue)(-1) = (-10)/color(blue)(-1)#

Therefore, #x = 10#

Hope this helps!

Eva Abramson · Answer

#x=10#

We can distribute the #5# on the left and the #-4# on the right to get

#10x+30=8x+20+3x#

Next, we can combine the #x# terms on the right to get

#10x+30=11x+20#

To make it easier, I'll switch the sides. I didn't do any math here, I just switched the sides:

#11x+20=10x+30#

We can subtract #10x# from both sides to get

#x+20=30#

Lastly, to completely isolate #x#, let's subtract #20# from both sides to get

#x=10#

Hope this helps!

Savannah Anderson · Answer

undefined To solve the equation 5(2x+6)=-4(-5-2x)+3x:

1. Distribute the terms inside the parentheses:
   10x + 30 = 20x + 20 + 3x

2. Combine like terms on both sides of the equation:
   10x + 30 = 23x + 20

3. Subtract 10x from both sides of the equation:
   30 = 13x + 20

4. Subtract 20 from both sides of the equation:
   10 = 13x

5. Divide both sides by 13 to isolate x:
   x = 10/13